这条语句单独执行，是没有问题的，可是放到shell里面，就会报错。怎么回事？

[ljj_jjl2008]

代码： 全选

#!/bin/bash

mode=1
home=""
if [ "$1" = "INIT" ]; then
  mode=2
  home=$2
else
  if [ "$1" = "START" ]; then
    echo "starting"
    mode=0
    home=$2
  else
    size=40 #unused in this program
    x=$1
    y=$2
    selectedgroup=$3
    raisemode=$4
    home="$5"
  fi
fi
if [ -z $home ]; then
  echo "fatal error: no /home/xxx found!"
  exit
fi
home="$home/.iconmenu2/bin"
cd $home

i=0
gc=0
s=""

while read buffer
do
  if [ -n "$buffer" ]; then
    if [ "${buffer:0:1}" != "#" ]; then
      if [ "${buffer:0:11}" = "baseconfig:" ]; then
        buffer0=${buffer#baseconfig:}
        xmain=`echo $buffer0|awk '{ print $1;}'`
        ymain=`echo $buffer0|awk '{ print $2;}'`
        sizemain=`echo $buffer0|awk '{ print $3;}'`
        gapmain=`echo $buffer0|awk '{ print $4;}'`
        sizesub=`echo $buffer0|awk '{ print $5;}'`
        gapsub=`echo $buffer0|awk '{ print $6;}'`
        raisemode=`echo $buffer0|awk '{ print $7;}'`
        autohidemainbutton=`echo $buffer0|awk '{ print $8;}'`
        autohideSubbutton=`echo $buffer0|awk '{ print $9;}'`
      fi
      if [ "${buffer:0:5}" = "group" ]; then
        group=`echo $buffer|awk '{ print $1;}'`
        result=${buffer#$group}
        group=${group#group}
        group=${group%#}
        if [ $mode -eq 2 ]; then
          echo "./iconrun1" $xmain $[ $ymain+$[ $gc * $[ $sizemain+$gapmain ] ] ] $sizemain $sizemain $raisemode $group $result $autohidemainbutton $autohideSubbutton
          `echo "./iconrun1" $xmain $[ $ymain+$[ $gc * $[ $sizemain+$gapmain ] ] ] $sizemain $sizemain $raisemode $group $result $autohidemainbutton $autohideSubbutton ` &
           exit
        fi
        if [ $mode -eq 0 ]; then
          if [ $group -gt 0 ]; then
            echo "./iconrun2 " $xmain $[ $ymain+$[ $[ $gc+1 ] * $[ $sizemain+$gapmain ] ] ] $sizemain $sizemain $raisemode $group $result
            `echo "./iconrun2 " $xmain $[ $ymain+$[ $[ $gc+1 ] * $[ $sizemain+$gapmain ] ] ] $sizemain $sizemain $raisemode $group $result ` &
            let "gc=$gc+1"
          fi
        fi
      else
        if [ "${buffer:0:6}" = "single" ]; then
          if [ $mode -eq 0 ]; then
            group=`echo $buffer|awk '{ print $1;}'`
            result=${buffer#$group}
            group=${group#single}
            group=${group%#}
            if [ $group>0 ]; then
              if [ $autohideSubbutton -eq 0 ]; then
                echo "./iconrun2c" $xmain $[ $ymain+$[ $[ $gc+1 ] * $[ $sizemain+$gapmain ] ] ] $sizemain $sizemain $raisemode $result &
                `echo "./iconrun2c" $xmain $[ $ymain+$[ $[ $gc+1 ] * $[ $sizemain+$gapmain ] ] ] $sizemain $sizemain $raisemode $result ` &
              else
                echo "./iconrun2d" $xmain $[ $ymain+$[ $[ $gc+1 ] * $[ $sizemain+$gapmain ] ] ] $sizemain $sizemain $raisemode $result
                `echo "./iconrun2d" $xmain $[ $ymain+$[ $[ $gc+1 ] * $[ $sizemain+$gapmain ] ] ] $sizemain $sizemain $raisemode $result ` &
              fi
              let "gc=$gc+1"
            fi
          fi
        else
          if [ $mode -eq 1 ]; then
            if [ $group -eq $selectedgroup ]; then
              if [ $autohideSubbutton -eq 0 ]; then
                echo "./iconrun2a" $[ $x+$gapsub+$[ $[ $sizesub+$gapsub ] * $i ] ] $[ $y-$[ $[ $sizesub-$sizemain ] / 2 ] ] $sizesub $sizesub $raisemode $buffer
                `echo "./iconrun2a" $[ $x+$gapsub+$[ $[ $sizesub+$gapsub ] * $i ] ] $[ $y-$[ $[ $sizesub-$sizemain ] / 2 ] ] $sizesub $sizesub $raisemode $buffer ` &
              else
                echo "./iconrun2b" $[ $x+$gapsub+$[ $[ $sizesub+$gapsub ] * $i ] ] $[ $y-$[ $[ $sizesub-$sizemain ] / 2 ] ] $sizesub $sizesub $raisemode $buffer
                `echo "./iconrun2b" $[ $x+$gapsub+$[ $[ $sizesub+$gapsub ] * $i ] ] $[ $y-$[ $[ $sizesub-$sizemain ] / 2 ] ] $sizesub $sizesub $raisemode $buffer ` &
              fi
              let "i=$i+1"
            fi
          fi
        fi
      fi
    fi
  fi
done < ../menu.rc

以上是一个shell，作用是从/menu.rc（配置文件）读取行，分析以后，调用“iconrun2b”等，分别显示一个图标。

/usr/share/icons/oxygen/48x48/devices/media-optical-dvd-video.png "dragon" "Dragon 媒体播放"

这是配置语句的一行，里面用了（双引号）作为转义符，一行作为iconrun2b的参数出现，形成下面的命令：

代码： 全选

./iconrun2c 100 864 64 64 1 /usr/share/icons/oxygen/48x48/devices/media-optical-dvd-video.png "dragon" "Dragon 媒体播放"

结果提示：

usage: iconrun2c x y width height lower/raise(0/1) image applicationToRun title

意思是参数数目不对。
其实，这条语句单独执行，是没有问题的，可是放到shell里面，一旦遇到双引号里面有空格的，就会报错。

请帮助，谢谢！！

[枫叶饭团]

把空格换成\ 转义？

[lilydjwg]

不懂 bash。这种情况建议用 Python 解决。当然，C 也可以。

[fnan]

这是配置语句的一行，里面用了（双引号）作为转义符，一行作为iconrun2b的参数出现，形成下面的命令：
代码:
./iconrun2c 100 864 64 64 1 /usr/share/icons/oxygen/48x48/devices/media-optical-dvd-video.png "dragon" "Dragon 媒体播放"

# 应该是命令没有正确形成，至少脚本里没见到引号。