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#!/bin/bash
declare coun = 0
while [ "$coun" -lt 10 ]
do
let $coun = "$coun + 1"
done
[root@localhost fugd]# ./j.sh
./j.sh: line 2: declare: `=': not a valid identifier
./j.sh: line 2: declare: `0': not a valid identifier
./j.sh: line 3: [: : integer expression expected
请高手帮看一下 这个错误是怎么回事？？？

city0011 写了：

代码： 全选

#!/bin/sh
coun=0
while [ "$coun" -lt 10 ]
do
        let "coun = $coun + 1"
done
exit 0
~     

#!/bin/bash
declare coun
coun = "0"
while [ "$coun" -lt 10 ]
do
let $coun = "$coun + 1"
done
exit 0
[root@localhost fugd]# ./j.sh
./j.sh: line 3: coun: command not found
./j.sh: line 4: [: : integer expression expected
我改了 按照楼上的 但还是不对啊～～～～～～～～

空格问题，=两边有空格是判断，无空格是赋值。

xiooli 写了：空格问题，=两边有空格是判断，无空格是赋值。

#!/bin/bash
declare coun = 1
while [ " $coun " -lt 10 ]
do
let $coun = " $coun + 1 "
done
exit 0


哪个位置缺少空格？？

是说 declare coun = 1 么 ，两边都有空格
[ " $coun " -lt 10 ]两边也都有空格

怎么回事？
能具体说下是哪个地方么？

deargodlove 写了：#!/bin/bash
declare coun = 1
while [ " $coun " -lt 10 ]
do
let $coun = " $coun + 1 "
done
exit 0


哪个位置缺少空格？？

是说 declare coun = 1 么 ，两边都有空格
[ " $coun " -lt 10 ]两边也都有空格

怎么回事？
能具体说下是哪个地方么？

赋值的时候,等号两边不能有空格,应该是coun=1, 而不是coun = 1

感谢楼上的各位