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lainme 写了：确实，你的目的就是合并。改名是为了用那个专门的软件来做合并这件事。

但其实你不该名，用cat就合并了，何必多做一步

想这样的结构：a.mkv000，a.mkv001，a.mkv002，a.mkv003

直接

cat a.mkv* > a.mkv

就可以了

anguste 写了：

lainme 写了：确实，你的目的就是合并。改名是为了用那个专门的软件来做合并这件事。

但其实你不该名，用cat就合并了，何必多做一步

想这样的结构：a.mkv000，a.mkv001，a.mkv002，a.mkv003

直接

cat a.mkv* > a.mkv

就可以了

呃，这样也可以的。我先前没有试过这个是因为在win下面用简单的copy拼接出来的视频是不能看的，不知何解。。。
当然，cat虽然简单但缺点是对于很大的文件无法得知合并的进度，也就不知道需要多少时间了。

anyway，学到很多，谢谢大家

anguste 写了：

fnan 写了：设文件在b文件夹，a.mkv000 改成 a.mkv_001 ,要加_不然就把另外的文件覆盖了，数字不必要连续，全部加一：
kose5@kose5-Aspire-4552:~$ cd b;ls -1|while read n;do a=($(sed 's#\(.*\)\([0-9]\{3\}\)$#\1 \2#' <<<$n ));mv $n ${a[0]}"_"$(printf "%03d" $((${a[1]/#?(0|00)}+1)));done;cd

代码： 全选

ls -1|while read n;do a=($(sed 's#\(.*\)\([0-9]\{3\}\)$#\1 \2#' <<<$n ));mv $n ${a[0]}"."$(printf "%03d" $((${a[1]/#?(0|00)}+1)));done

此法可行，感激涕零！！！

在我的实际应用中把_替换成.了

想问下如果文件名不是a，应该改哪些地方？

kose3@kose3-desktop:~$ ls b
kose3@kose3-desktop:~$ touch b/{a,b,c}.mkv{000,001,002,003}
kose3@kose3-desktop:~$ ls b
a.mkv000 a.mkv001 a.mkv002 a.mkv003 b.mkv000 b.mkv001 b.mkv002 b.mkv003 c.mkv000 c.mkv001 c.mkv002 c.mkv003
kose3@kose3-desktop:~$ cd b;ls -1|while read n;do a=($(sed 's#\(.*\)\([0-9]\{3\}\)$#\1 \2#' <<<$n ));mv $n ${a[0]}"."$(printf "%03d" $((${a[1]/#?(0|00)}+1)));done;cd
kose3@kose3-desktop:~$ ls b
a.mkv.001 a.mkv.002 a.mkv.003 a.mkv.004 b.mkv.001 b.mkv.002 b.mkv.003 b.mkv.004 c.mkv.001 c.mkv.002 c.mkv.003 c.mkv.004
kose3@kose3-desktop:~$

kose3@kose3-desktop:~/b$ ls
a.mkv000 a.mkv001 a.mkv002 a.mkv003 b.mkv000 b.mkv001 b.mkv002 b.mkv003 c.mkv000 c.mkv001 c.mkv002 c.mkv003
kose3@kose3-desktop:~/b$ rename 's/mkv/mkv\./' a.*
kose3@kose3-desktop:~/b$ ls
a.mkv.000 a.mkv.001 a.mkv.002 a.mkv.003 b.mkv000 b.mkv001 b.mkv002 b.mkv003 c.mkv000 c.mkv001 c.mkv002 c.mkv003
kose3@kose3-desktop:~/b$ rename 's/mkv/mkv\./' *.*
kose3@kose3-desktop:~/b$ ls
a.mkv..000 a.mkv..001 a.mkv..002 a.mkv..003 b.mkv.000 b.mkv.001 b.mkv.002 b.mkv.003 c.mkv.000 c.mkv.001 c.mkv.002 c.mkv.003
kose3@kose3-desktop:~/b$ rm *
kose3@kose3-desktop:~/b$ touch {a,b,c}.mkv{000,001,002,003}
kose3@kose3-desktop:~/b$ rename 's/mkv/mkv\./' *.mkv*
kose3@kose3-desktop:~/b$ ls
a.mkv.000 a.mkv.001 a.mkv.002 a.mkv.003 b.mkv.000 b.mkv.001 b.mkv.002 b.mkv.003 c.mkv.000 c.mkv.001 c.mkv.002 c.mkv.003
kose3@kose3-desktop:~/b$

kose3@kose3-desktop:~/b$ ls
a.mkv000 a.mkv002 a.mkv004
kose3@kose3-desktop:~/b$ ls -1|while read n;do a=($(sed 's#\(.*\)\([0-9]\{3\}\)$#\1 \2#' <<<$n ));mv $n ${a[0]}"."$(printf "%03d" $((${a[1]/#?(0|00)}+1)));done
kose3@kose3-desktop:~/b$ ls
a.mkv.001 a.mkv.003 a.mkv.005

kose3@kose3-desktop:~/b$ rm *
kose3@kose3-desktop:~/b$ touch a.mkv{000,002,004}
kose3@kose3-desktop:~/b$ ls
a.mkv000 a.mkv002 a.mkv004
kose3@kose3-desktop:~/b$ rename 's/mkv/mkv\./' a.*
kose3@kose3-desktop:~/b$ ls
a.mkv.000 a.mkv.002 a.mkv.004

fnan 写了：如果想要这效果：

kose3@kose3-desktop:~/b$ ls
a.mkv000 a.mkv002 a.mkv004
kose3@kose3-desktop:~/b$ ls -1|while read n;do a=($(sed 's#\(.*\)\([0-9]\{3\}\)$#\1 \2#' <<<$n ));mv $n ${a[0]}"."$(printf "%03d" $((${a[1]/#?(0|00)}+1)));done
kose3@kose3-desktop:~/b$ ls
a.mkv.001 a.mkv.003 a.mkv.005

rename可以吗？

kose3@kose3-desktop:~/b$ rm *
kose3@kose3-desktop:~/b$ touch a.mkv{000,002,004}
kose3@kose3-desktop:~/b$ ls
a.mkv000 a.mkv002 a.mkv004
kose3@kose3-desktop:~/b$ rename 's/mkv/mkv\./' a.*
kose3@kose3-desktop:~/b$ ls
a.mkv.000 a.mkv.002 a.mkv.004

$ touch a.mkv{000,002,004}
$ rename -v 's/(?<![.\d])(\d++)$/sprintf ".%0".length($1)."d",$1+1/e' * 
a.mkv000 renamed as a.mkv.001
a.mkv002 renamed as a.mkv.003
a.mkv004 renamed as a.mkv.005
$ rename -v 's/(?<![.\d])(\d++)$/sprintf ".%0".length($1)."d",$1+1/e' *
$ touch a.mkv{000000,00002,00000000004}
$ rename -v 's/(?<![.\d])(\d++)$/sprintf ".%0".length($1)."d",$1+1/e' *
a.mkv000000 renamed as a.mkv.000001
a.mkv00000000004 renamed as a.mkv.00000000005
a.mkv00002 renamed as a.mkv.00003
$ ls
a.mkv.00000000005  a.mkv.000001  a.mkv.00003  a.mkv.001  a.mkv.003  a.mkv.005

fnan 写了：如果HJSplit的软件能自动按文件名把文件夹里的上万视频自动处理好，用bash命令自动处理上万的文件名是 有价值的，rename能自动搞定不同的视频名吗？cat处理一个视频的零散文件名还可以，上万呢？还是要bash语法上阵，有点技术细节狂，不要误会pk。

ChenFengyuan 写了：to fnan,你的bash也太长了。。。。。原来是要有+1的效果。。。。
交给perl好了。写得又短又漂亮。

ls
a.12mkv000103 a.mkv000 a.mkv000000 a.mkv00000000004 a.mkv00002 a.mkv002 a.mkv004
ls -1|while read n;do z=${n/#*[!0-9]};mv $n ${n/%*([0-9])}$(printf ".%0${#z}d" $((${z/#*(0)}+1)));done
ls
a.12mkv.000104 a.mkv.00000000005 a.mkv.000001 a.mkv.00003 a.mkv.001 a.mkv.003 a.mkv.005
ls -1|while read n;do z=${n/#*[!0-9]};mv $n ${n/%*([0-9])}$(printf ".%0${#z}d" $((${z/#*(0)}+1)));done
ls
a.12mkv..000105 a.mkv..00000000006 a.mkv..000002 a.mkv..00004 a.mkv..002 a.mkv..004 a.mkv..006

ls
a.12mkv000103 a.mkv000 a.mkv000000 a.mkv00000000004 a.mkv00002 a.mkv002 a.mkv004
rename -v 's/(?<![.\d])(\d++)$/sprintf ".%0".length($1)."d",$1+1/e' *
ls
a.12mkv.000104 a.mkv.00000000005 a.mkv.000001 a.mkv.00003 a.mkv.001 a.mkv.003 a.mkv.005
rename -v 's/(?<![.\d])(\d++)$/sprintf ".%0".length($1)."d",$1+1/e' *
ls
a.12mkv.000104 a.mkv.00000000005 a.mkv.000001 a.mkv.00003 a.mkv.001 a.mkv.003 a.mkv.005

我就是我2 写了：觉得ee的方法很好，简洁
不过先要安装perl-rename

fnan 写了：

我就是我2 写了：觉得ee的方法很好，简洁
不过先要安装perl-rename

是不错，不够通用。