试试这个吧，也许会快点
[c]/*
Stolen shamelessly from c-Chaz-Schlarp.c
My big optimization is to start with a random string, find its md5,
and then use that computed md5 as the next source string, with one
hex digit changed. My theory is that since each md5 is effectively
random, and there's no correlation between adjacent md5s, that
changing one digit is just as good as creating a new string of 16
new digits. This lets me do only two expensive rand() calls per
try.
*/
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>
#define NHEXDIGITS 32
#define PROGRESS_MOD (1024*1024)
const unsigned int T[64] = {
0xd76aa478, 0xe8c7b756, 0x242070db, 0xc1bdceee, 0xf57c0faf, 0x4787c62a, 0xa8304613, 0xfd469501,
0x698098d8, 0x8b44f7af, 0xffff5bb1, 0x895cd7be, 0x6b901122, 0xfd987193, 0xa679438e, 0x49b40821,
0xf61e2562, 0xc040b340, 0x265e5a51, 0xe9b6c7aa, 0xd62f105d, 0x02441453, 0xd8a1e681, 0xe7d3fbc8,
0x21e1cde6, 0xc33707d6, 0xf4d50d87, 0x455a14ed, 0xa9e3e905, 0xfcefa3f8, 0x676f02d9, 0x8d2a4c8a,
0xfffa3942, 0x8771f681, 0x6d9d6122, 0xfde5380c, 0xa4beea44, 0x4bdecfa9, 0xf6bb4b60, 0xbebfbc70,
0x289b7ec6, 0xeaa127fa, 0xd4ef3085, 0x04881d05, 0xd9d4d039, 0xe6db99e5, 0x1fa27cf8, 0xc4ac5665,
0xf4292244, 0x432aff97, 0xab9423a7, 0xfc93a039, 0x655b59c3, 0x8f0ccc92, 0xffeff47d, 0x85845dd1,
0x6fa87e4f, 0xfe2ce6e0, 0xa3014314, 0x4e0811a1, 0xf7537e82, 0xbd3af235, 0x2ad7d2bb, 0xeb86d391
};
const unsigned int passdata[128] = {
0, 7, 1, 12, 2, 17, 3, 22, 4, 7, 5, 12, 6, 17, 7, 22, 8, 7, 9, 12, 10, 17, 11, 22, 12, 7, 13, 12, 14, 17, 15, 22,
1, 5, 6, 9, 11, 14, 0, 20, 5, 5, 10, 9, 15, 14, 4, 20, 9, 5, 14, 9, 3, 14, 8, 20, 13, 5, 2, 9, 7, 14, 12, 20,
5, 4, 8, 11, 11, 16, 14, 23, 1, 4, 4, 11, 7, 16, 10, 23, 13, 4, 0, 11, 3, 16, 6, 23, 9, 4, 12, 11, 15, 16, 2, 23,
0, 6, 7, 10, 14, 15, 5, 21, 12, 6, 3, 10, 10, 15, 1, 21, 8, 6, 15, 10, 6, 15, 13, 21, 4, 6, 11, 10, 2, 15, 9, 21
};
typedef struct md5_state_s {
unsigned int count[2];
unsigned int abcd[4];
unsigned char buf[64];
} md5_state_t;
static void md5_process(md5_state_t *pms, const unsigned char *data)
{
unsigned int a = pms->abcd[0];
unsigned int b = pms->abcd[1];
unsigned int c = pms->abcd[2];
unsigned int d = pms->abcd[3];
unsigned int t;
unsigned int xbuf[16];
const unsigned int *X;
int pass = 0;
if(!((data - (const unsigned char *)0) & 3)) {
X = (const unsigned int *)data;
}
else {
memcpy(xbuf, data, 64);
X = xbuf;
}
for(pass = 0; pass < 16; pass++) {
#define SET(a, b, c, d, k, s, Ti) t = a + (pass < 4 ? (((b) & (c)) | (~(b) & (d))) : (pass < 8 ? (((b) & (d)) | ((c) & ~(d))) : (pass < 12 ? ((b) ^ (c) ^ (d)) : ((c) ^ ((b) | ~(d)))))) + X[k] + Ti; a = (((t) << (s)) | ((t) >> (32 - (s)))) + b
SET(a, b, c, d, passdata[pass*8+0], passdata[pass*8+1], T[pass*4+0]);
SET(d, a, b, c, passdata[pass*8+2], passdata[pass*8+3], T[pass*4+1]);
SET(c, d, a, b, passdata[pass*8+4], passdata[pass*8+5], T[pass*4+2]);
SET(b, c, d, a, passdata[pass*8+6], passdata[pass*8+7], T[pass*4+3]);
#undef SET
}
pms->abcd[0] += a;
pms->abcd[1] += b;
pms->abcd[2] += c;
pms->abcd[3] += d;
}
void md5_init(md5_state_t *pms)
{
pms->count[0] = 0;
pms->count[1] = 0;
pms->abcd[0] = 0x67452301;
pms->abcd[1] = 0xefcdab89;
pms->abcd[2] = 0x98badcfe;
pms->abcd[3] = 0x10325476;
}
void md5_append(md5_state_t *pms, const unsigned char *data, int nbytes)
{
const unsigned char *p = data;
const int offset = (pms->count[0] >> 3) & 63;
unsigned int nbits = (unsigned int)(nbytes << 3);
int left = nbytes;
if (nbytes <= 0) {
return;
}
pms->count[1] += nbytes >> 29;
pms->count[0] += nbits;
if (pms->count[0] < nbits) {
pms->count[1]++;
}
if (offset) {
const int copy = (offset + nbytes > 64 ? 64 - offset : nbytes);
memcpy(pms->buf + offset, p, copy);
if (offset + copy < 64) {
return;
}
p += copy;
left -= copy;
md5_process(pms, pms->buf);
}
for(; left >= 64; p += 64, left -= 64) {
md5_process(pms, p);
}
if (left) {
memcpy(pms->buf, p, left);
}
}
void md5_finish(md5_state_t *pms, unsigned char digest[16])
{
static const unsigned char pad[64] = {
128, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
};
unsigned char data[8];
int i;
for (i = 0; i < 8; ++i) {
data[i] = (unsigned char)(pms->count[i >> 2] >> ((i & 3) << 3));
}
md5_append(pms, pad, ((55 - (pms->count[0] >> 3)) & 63) + 1);
md5_append(pms, data, 8);
for(i = 0; i < 16; ++i) {
digest[i] = (unsigned char)(pms->abcd[i >> 2] >> ((i & 3) << 3));
}
}
const char * md5(const char *input, int inputlength)
{
md5_state_t state;
static unsigned char digest[16];
static char hex_output[16*2 + 1];
int di;
md5_init(&state);
md5_append(&state, (const unsigned char *)input, inputlength);
md5_finish(&state, digest);
for (di = 0; di < 16; ++di) {
sprintf(hex_output + di * 2, "%02x", digest[di]);
}
return hex_output;
}
int main( void )
{
static const char digits[] = "0123456789abcdef";
unsigned long ntries = 0;
char source[33];
int i;
const time_t start = time(NULL);
srand(start);
memset( source, 0, sizeof( source ) );
for ( i = 0; i < NHEXDIGITS; i++ ) {
source[ i ] = digits[ rand() % 16 ];
}
while (1) {
if ( ntries % PROGRESS_MOD == 0 ) {
const time_t now = time(NULL);
const time_t elapsed = now - start;
const float rate = elapsed ? ((float)ntries/(float)elapsed) : 0;
printf( "# %lu, %6lu, %12lu, %9.1f, %-24.24s, %s\n",
now, elapsed, ntries, rate, ctime(&now), source );
fflush(stdout);
}
++ntries;
const char * const calculated_md5 = md5( source, NHEXDIGITS );
if ( memcmp( calculated_md5, source, NHEXDIGITS ) == 0 ) {
printf("We found it: %s matches %s\n", source, calculated_md5 );
exit(0);
}
/* Rather than come up with all random digits, we just randomize one digit */
memcpy( source, calculated_md5, NHEXDIGITS );
source[ rand() % NHEXDIGITS ] = digits[ rand() % 16 ];
}
return 0;
}
[/c]
这个 git 页上有用各种语言写的解决此问题的方法：
https://github.com/elliottkember/The-Kember-Identity
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