Ubuntu中文论坛

#!/bin/bash
#Postgraduate countdown for Jessie

PATH=/bin:/sbin:/usr/bin:usr/sbin:usr/local/bin:usr/local/sbin:~/bin
export PATH

echo "This timer will try to calculate: "
echo "How many days before your postgraduate entrance examination."
read -p "Please input your examination date (YYYYMMDD ex>20170101): " dateshuru

datetianshu=$(echo $dateshuru | grep '[0-9]\{8\}')
if [ "datetianshu" == "" ];then
echo "You input the wrong date format."
exit 1
fi

declare -i datezuihou=`date --date="$dateshuru" +%s`
declare -i datexianzai=`date +%s`
declare -i datezonggong=$(($datezuihou-$datexianzai))
declare -i datetianshu=$(($datezonggong/60/60/24))

if [ "$datezonggong" -lt "0" ];then
echo "You had been examination before "$((-l*$datezonggong))" days ago"
else
declare -i datexiaoshi=$(($(($datezonggong-$datetianshu*60*60*24))/60/60))
echo "You will postgraduate after $datetianshu days and $datexiaoshi hours."


我输入20171224没问题，可以显示出时间，可是如果我输入过去的时间，它老是显示
Please input your examination date (YYYYMMDD ex>20170101): 20170805
You had been examination before 0 days ago
按道理来说不应该老是0天啊～

哪位大神可以帮忙看下哪儿出问题了吗？我是参考着一个范本做的，对“$((-l*$datezonggong))”还不是很理解，尤其是里面“-l*”这个写法没弄明白，还望大神多多指教。

好吧，同志们，我知道了，就是因为“-l*”的原因，所以老是显示0天，把这个去掉就能显示出准确的天数了，只不过是负的。
我猜测“-l*”这个是用来修正负数的。

不知道是谁把-1看成了-l，另外那算出来的是秒数，不是天数

astolia 写了：不知道是谁把-1看成了-l，另外那算出来的是秒数，不是天数

恩恩，今晚我也发现了，尝试着改成了数字1，OK啦～